Bhargav's Ultimate Blog

Sunday, March 13, 2016

JQuery with XSLT

I have been trying some XML transformation with XSLT and as I saw the XML can be transformed into HTML, I thought why not include JQuery into the transformation that I am doing.

I took a sample XML, in XSL I included the HTML and javascript along with JQuery that I wanted.

XML to be transformed:

<?xml version="1.0"?>
 <root>
  <node_1>
   <element_1>Data of element 1</element_1>
   <element_2>Data of element 2</element_2>
   <element_3>Data of element 3</element_3>
  </node_1>
 </root>

XSL used to transform the above XML:

<?xml version="1.0"?>
<xsl:stylesheet version="1.0" xmlns="http://www.w3.org/1999/xhtml" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes"/>
 <xsl:template match="/">
 
  <html>
   <head>
    <link rel="stylesheet" href="http://code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css"/>
<script src="http://code.jquery.com/jquery-1.10.2.js"></script>
  <script src="http://code.jquery.com/ui/1.11.4/jquery-ui.js"></script>
    <script>
     $(document).ready(
     $(function() {
      $("#root").accordion();
     }));
    </script>
   </head>
   <body style="background-color:red;">
   <h1 style="text-align:center;color:white;">JQuery accordion</h1>
    <div id="root">
     <xsl:for-each select="/root/node_1/*">
     <xsl:variable name="counter" select="position()" />
      <h6><xsl:value-of select="concat('Step No.',$counter)"/></h6>
      <div>
       <p><xsl:value-of select="."/></p>
       <textarea rows="4" cols="100"></textarea>
      </div>
     </xsl:for-each>
    </div>
    
   </body>
  </html>
 </xsl:template>
</xsl:stylesheet>

In the above XSL transformation, I included the JQuery CDNs and javascript code to make the accordion available and I used a counter variable to dynamically name the accordion steps.

In the XSL I am accessing and looping through node_1's child elements and using the data of the elements in each steps of the accordion.

For transformation I used a java code based on the javax.xml.transform package and it's classes.

Java code used to transform and generate HTML:

package com.java;

import java.io.File;

import javax.xml.transform.Transformer;
import javax.xml.transform.TransformerConfigurationException;
import javax.xml.transform.TransformerException;
import javax.xml.transform.TransformerFactory;
import javax.xml.transform.stream.StreamResult;
import javax.xml.transform.stream.StreamSource;

public class XSLTest {

 public XSLTest() {

 }

 public static void main(String[] args) {
  TransformerFactory factory = TransformerFactory.newInstance();
  StreamSource xslStream = new StreamSource(new File(
    "demoXslFile1.xsl"));
  Transformer transformer;
  try {
   transformer = factory.newTransformer(xslStream);
   StreamSource in = new StreamSource(new File(
     "demoFile1.xml"));
   StreamResult out = new StreamResult(new File(
     "htmlFile1.html"));
   transformer.transform(in, out);
  } catch (TransformerConfigurationException e) {
   e.printStackTrace();
  } catch (TransformerException e) {
   e.printStackTrace();
  }
 }
}

I used transformer class to transform the XML input to HTML output using XSL transformation file.

The transform method of Transformer class takes StreamSource and StreamResult type variables as parameters.

StreamSource variable holds the xml source file.

StreamResult variable holds the final html file where the html has to be put into.

Another StreamSource instance variable holds xsl file.

The TransformerFactory class' instance variable holds reference to a fresh object. The variable then can be used to call newTransformer method which takes xsl file's StreamSource variable as method paramter.

The Transformer class' instance variable references the above.

XML transformed into HTML:

<html xmlns="http://www.w3.org/1999/xhtml">
 <head>
  <META http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <link rel="stylesheet" href="http://code.jquery.com/ui/1.11.4/themes/smoothness/jquery-ui.css">
  <script src="http://code.jquery.com/jquery-1.10.2.js"></script>
  <script src="http://code.jquery.com/ui/1.11.4/jquery-ui.js"></script><script>
   $(document).ready(
    $(function() {
     $("#root").accordion();
   }));
  </script>
 </head>
 <body style="background-color:red;">
  <h1 style="text-align:center;color:white;">JQuery accordion</h1>
  <div id="root">
   <h6>Step No.1</h6>
   <div>
    <p>Data of element 1</p>
    <textarea rows="4" cols="100"></textarea>
   </div>
   <h6>Step No.2</h6>
   <div>
    <p>Data of element 2</p>
    <textarea rows="4" cols="100"></textarea>
   </div>
   <h6>Step No.3</h6>
   <div>
    <p>Data of element 3</p>
    <textarea rows="4" cols="100"></textarea>
   </div>
  </div>
 </body>
</html>

HTML rendering:

Applications of XSLT are just awesome, ability to transform the XML data into a structured format is just amazing.

Sunday, January 31, 2016

Sending text email from Java using Apache Commons Email

In this post, I wanted to show how to send an email using Apache Commons Email.

In this post I wanted to cover:

The program written in Java to send emails.
Challenges that I faced when sending emails.

Things one requires:

Eclipse.
Java.
Apache Commons Email library.
Two Gmail accounts (One acts as from address and one as to address) or One Gmail account (From and to address).

Apache Commons Email library can be downloaded from here: Apache Commons Email.

Configuration necessary in Eclipse before writing java program using Apache Commons Email library.

Create a Java project.

Right click on the project and choose properties.

In the properties choose Java Build Path and in Libraries tab click the button Add External Jars button on the right side.

Choose the jar that was downloaded from Apache website and add it.

Click OK and create a new Java class.

My Java class with Apache Commons Email code is as below:

package com.java;

import org.apache.commons.mail.DefaultAuthenticator;
import org.apache.commons.mail.Email;
import org.apache.commons.mail.EmailException;
import org.apache.commons.mail.SimpleEmail;

public class ApacheMailSample {

 public static void main(String[] args) {
  Email email = new SimpleEmail();
  email.setHostName("smtp.gmail.com");
  email.setSmtpPort(465);
  email.setAuthenticator(new DefaultAuthenticator("<sender>@gmail.com", "<sendersPass>"));
  email.setSSLOnConnect(true);
  email.setStartTLSEnabled(true);
  email.setStartTLSRequired(true);
  try {
   email.setFrom("<sender>@gmail.com");
   email.setSubject("Test email from java program");
   email.addTo("<recipient>@gmail.com");
   email.send();
  } catch (EmailException e) {
   e.printStackTrace();
  }
 }

}

In the above code, I have created an object of class SimpleEmail.

I have set host to smtp.gmail.com, smtp port to 465.

To the DefaultAuthenticator's constructor I have passed Username (from address) and Password.

According to Google, the following has to be configured to send an email.

SMTP HOST: smtp.gmail.com

SMTPPORT: 587 (465 for SSL)

USE SSL: Optional

SMTP Auth: Login

Source: SMTP Host details.

I have used port 465 in my java program and set SSL to true using method setSSLOnConnect.

I have set TLSEnabled to true using the methods setStartTLSEnabled and setStartTLSRequired.

Using methods setFrom, setSubject, addTo one can add from address, set subject of the email, set to address respectively.

One will have to send email using method send.

Challenges that I have faced:

Initially I was getting AuthenticationFailedException, on my google search I found out that we have to enable access to less secure apps on from email address at this link: Less Secure Apps Setting. I had to click turn on to let my java program access the email.
I have initially used smtp.googlemail.com and I was getting a message, couldn't connect to smtp host with response -1. After I changed the smtp host to smtp.gmail.com I was able to send emails.
Without having methods setStartTLSEnabled and setStartTLSRequired, I was getting the exception AuthenticationFailedException.

After I resolved the above errors, I was able to send email successfully from one email address to another (Gmail).

Sunday, November 29, 2015

Using JQuery to play a GIF on hovering the mouse over.

I used JQuery to implement the hover functionality.

The objective is to play a GIF image when the mouse is on the image and image should go static when the mouse is out of image area.

Once the mouse is out of the image area, the image goes static.

HTML + JQuery code:

<html>
 <head>
  <script src="http://code.jquery.com/jquery-1.11.3.min.js"></script>
  <script src="http://code.jquery.com/jquery-migrate-1.2.1.min.js"></script>
 </head>
 <body>
  <img src="image_1_static.jpg" id="id1"/>
  <script>
   $(document).ready(function() {
    $("#id1").hover(
     function() {
      $(this).attr("src", "image_1.gif")
     }, function() {
      $(this).attr("src", "image_1_static.jpg")
     }
    );
   });
  </script>
 </body>
</html>

For achieving the above, I took a GIF (image_1.gif), opened the GIF in mspaint and saved it as jpeg/jpg image (image_1_static.jpg), now I have a static image and a GIF.

I took src for the img as the static image (image_1_static.jpg) and in the hover, I have written two functions one that accepts gif (image_1.gif) when mouse hovers over the img area and one that accepts jpeg/jpg (image_1_static.jpg) when mouse is out of img area.

This functionality can be very useful for creating menu icons in a website. When user places mouse over, icon plays.

Suggestions are well appreciated and happy learning.